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Units and Measurements question

2023 · 29 Jan · Shift 2 · Q47
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Units and Measurements question

2023 · 29 Jan · Shift 2 · Q47

JEE MainPhysicsUnits and MeasurementsMCQ+4 / −1
The equation of a circle is given by x2+y2=a2x^2+y^2=a^2x2+y2=a2, where a is the radius. If the equation is modified to change the origin other than (0, 0), then find out the correct dimensions of A and B in a new equation : (x−At)2+(y−tB)2=a2{(x - At)^2} + {\left( {y - {t \over B}} \right)^2} = {a^2}(x−At)2+(y−Bt​)2=a2. The dimensions of t is given as [T−1][\mathrm{T^{-1}]}[T−1].
  1. A
    A=[L−1T−1],B=[LT−1]\mathrm{A=[L^{-1}T^{-1}],B=[LT^{-1}]}A=[L−1T−1],B=[LT−1]
  2. B
    A=[L−1T−1],B=[LT]\mathrm{A=[L^{-1}T^{-1}],B=[LT]}A=[L−1T−1],B=[LT]
  3. C
    A=[LT],B=[L−1T−1]\mathrm{A=[LT],B=[L^{-1}T^{-1}]}A=[LT],B=[L−1T−1]
  4. D
    A=[L−1T],B=[LT−1]\mathrm{A=[L^{-1}T],B=[LT^{-1}]}A=[L−1T],B=[LT−1]
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