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Units and Measurements question

2022 · 24 Jun · Shift 1 · Q47
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Units and Measurements question

2022 · 24 Jun · Shift 1 · Q47

JEE MainPhysicsUnits and MeasurementsMCQ+4 / −1
Identify the pair of physical quantities which have different dimensions:
  1. A
    Wave number and Rydberg's constant
  2. B
    Stress and Coefficient of elasticity
  3. C
    Coercivity and Magnetisation
  4. D
    Specific heat capacity and Latent heat
View written solutionFree

Correct answer: D

  1. We compare dimensions of each pair.

A pair has different dimensions only if their dimensional formulas are not the same.


  1. Option A: Wave number and Rydberg's constant
  • Wave number = number of waves per unit length [wave number]=L−1[\text{wave number}] = L^{-1}[wave number]=L−1
  • Rydberg's constant appears in 1λ=R(1n12−1n22)\frac{1}{\lambda} = R\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)λ1​=R(n12​1​−n22​1​) so [R]=L−1[R] = L^{-1}[R]=L−1

So both have same dimensions.


  1. Option B: Stress and Coefficient of elasticity
  • Stress = force/area [stress]=[F][A]=MLT−2L2=ML−1T−2[\text{stress}] = \frac{[F]}{[A]} = \frac{MLT^{-2}}{L^2} = ML^{-1}T^{-2}[stress]=[A][F]​=L2MLT−2​=ML−1T−2
  • Coefficient of elasticity (modulus of elasticity) = stress/strain

Since strain is dimensionless, [coefficient of elasticity]=[stress]=ML−1T−2[\text{coefficient of elasticity}] = [\text{stress}] = ML^{-1}T^{-2}[coefficient of elasticity]=[stress]=ML−1T−2

So both have same dimensions.


  1. Option C: Coercivity and Magnetisation
  • Magnetisation MMM has unit magnetic dipole moment per unit volume. Its SI unit is A/mA/mA/m.
  • Coercivity HcH_cHc​ is magnetic field intensity required to reduce magnetisation to zero. Its SI unit is also A/mA/mA/m.

Hence, [coercivity]=[magnetisation][\text{coercivity}] = [\text{magnetisation}][coercivity]=[magnetisation]

So both have same dimensions.


  1. Option D: Specific heat capacity and Latent heat
  • Specific heat capacity: c=Qm ΔTc = \frac{Q}{m\,\Delta T}c=mΔTQ​ So, [c]=ML2T−2MΘ=L2T−2Θ−1[c] = \frac{ML^2T^{-2}}{M\Theta} = L^2T^{-2}\Theta^{-1}[c]=MΘML2T−2​=L2T−2Θ−1

  • Latent heat (specific latent heat): L=QmL = \frac{Q}{m}L=mQ​ So, [L]=ML2T−2M=L2T−2[L] = \frac{ML^2T^{-2}}{M} = L^2T^{-2}[L]=MML2T−2​=L2T−2

These are different because specific heat capacity contains Θ−1\Theta^{-1}Θ−1, while latent heat does not.


  1. Conclusion

The pair having different dimensions is: D: Specific heat capacity and Latent heat\boxed{\text{D: Specific heat capacity and Latent heat}}D: Specific heat capacity and Latent heat​

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