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Units and Measurements question

2022 · 24 Jun · Shift 2 · Q46
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Units and Measurements question

2022 · 24 Jun · Shift 2 · Q46

JEE MainPhysicsUnits and MeasurementsMCQ+4 / −1
Identify the pair of physical quantities that have same dimensions:
  1. A
    velocity gradient and decay constant
  2. B
    Wien's constant and Stefan constant
  3. C
    angular frequency and angular momentum
  4. D
    wave number and Avogadro number
View written solutionFree

Correct answer: A

  1. We compare the dimensions of each quantity in the given pairs.

  1. Option A: velocity gradient and decay constant
  • Velocity gradient means rate of change of velocity with distance: velocity gradient=vx\text{velocity gradient} = \frac{v}{x}velocity gradient=xv​

  • Dimensions of velocity: [v]=[LT−1][v] = [L T^{-1}][v]=[LT−1]

  • Therefore, [vx]=[LT−1][L]=[T−1]\left[\frac{v}{x}\right] = \frac{[L T^{-1}]}{[L]} = [T^{-1}][xv​]=[L][LT−1]​=[T−1]

  • Decay constant λ\lambdaλ comes from radioactive decay law: N=N0e−λtN = N_0 e^{-\lambda t}N=N0​e−λt

  • Since λt\lambda tλt must be dimensionless, [λ]=[T−1][\lambda] = [T^{-1}][λ]=[T−1]

So both have the same dimensions: [T−1][T^{-1}][T−1]

Hence, Option A is correct.


  1. Option B: Wien's constant and Stefan constant
  • Wien's displacement law: λmax⁡T=b\lambda_{\max} T = bλmax​T=b

  • Therefore dimensions of Wien's constant bbb are: [b]=[L][Θ][b] = [L][\Theta][b]=[L][Θ] where Θ\ThetaΘ denotes temperature.

  • Stefan-Boltzmann law: PA=σT4\frac{P}{A} = \sigma T^4AP​=σT4

  • So, [σ]=[P/A][T4][\sigma] = \frac{[P/A]}{[T^4]}[σ]=[T4][P/A]​

  • Power per unit area: [PA]=[ML2T−3][L2]=[MT−3]\left[\frac{P}{A}\right] = \frac{[M L^2 T^{-3}]}{[L^2]} = [M T^{-3}][AP​]=[L2][ML2T−3]​=[MT−3]

  • Hence, [σ]=[MT−3Θ−4][\sigma] = [M T^{-3} \Theta^{-4}][σ]=[MT−3Θ−4]

These are not the same.

So Option B is incorrect.


  1. Option C: angular frequency and angular momentum
  • Angular frequency: [ω]=[T−1][\omega] = [T^{-1}][ω]=[T−1]

  • Angular momentum: L=rp=r(mv)L = r p = r(mv)L=rp=r(mv)

  • Therefore, [L]=[L][MLT−1]=[ML2T−1][L] = [L] [M L T^{-1}] = [M L^2 T^{-1}][L]=[L][MLT−1]=[ML2T−1]

These are not the same.

So Option C is incorrect.


  1. Option D: wave number and Avogadro number
  • Wave number is: νˉ=1λ\bar{\nu} = \frac{1}{\lambda}νˉ=λ1​

  • Therefore, [νˉ]=[L−1][\bar{\nu}] = [L^{-1}][νˉ]=[L−1]

  • Avogadro number is a pure count, so it is dimensionless: [NA]=[1][N_A] = [1][NA​]=[1]

These are not the same.

So Option D is incorrect.


  1. Final conclusion

Only Option A has the same dimensions in the pair.

A\boxed{A}A​


  1. Comparison with stored correct answer

Stored correct answer: A

My derived answer: A

They match.

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