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Units and Measurements question

2021 · 27 Aug · Shift 2 · Q52
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Units and Measurements question

2021 · 27 Aug · Shift 2 · Q52

JEE MainPhysicsUnits and MeasurementsMCQ+4 / −1
Match List - I with List - II.

List - I List - II
(a) RH{R_H}RH​ (Rydberg constant) (i) kg m−1s−1kg\,{m^{ - 1}}{s^{ - 1}}kgm−1s−1
(b) h (Planck's constant) (ii) kg m2s−1kg\,{m^2}{s^{ - 1}}kgm2s−1
(c) μB{\mu _B}μB​ (Magnetic field energy density) (iii)  m−1\,{m^{ - 1}}m−1
(d) η\etaη (coefficient of viscocity) (iv) kg m−1s−2kg\,{m^{ - 1}}{s^{ - 2}}kgm−1s−2


Choose the most appropriate answer from the options given below :
  1. A
    (a)-(ii), (b)-(iii), (c)-(iv), (d)-(i)
  2. B
    (a)-(iii), (b)-(ii), (c)-(iv), (d)-(i)
  3. C
    (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
  4. D
    (a)-(iii), (b)-(ii), (c)-(i), (d)-(iv)
View written solutionFree

Correct answer: B

  1. Find the SI units of each quantity in List-I

(a) RHR_HRH​ : Rydberg constant

The Rydberg constant appears in spectroscopy equations like 1λ=RH(1n12−1n22)\frac{1}{\lambda}=R_H\left(\frac{1}{n_1^2}-\frac{1}{n_2^2}\right)λ1​=RH​(n12​1​−n22​1​) Since 1/λ1/\lambda1/λ has unit of inverse length, [RH]=m−1[R_H]=m^{-1}[RH​]=m−1 So, (a)→(iii)(a) \to (iii)(a)→(iii)


(b) hhh : Planck's constant

From E=hνE=h\nuE=hν we have [h]=[E][ν]=kg m2 s−2s−1=kg m2 s−1[h]=\frac{[E]}{[\nu]}=\frac{kg\,m^2\,s^{-2}}{s^{-1}}=kg\,m^2\,s^{-1}[h]=[ν][E]​=s−1kgm2s−2​=kgm2s−1 So, (b)→(ii)(b) \to (ii)(b)→(ii)


(c) μB\mu_BμB​ : Magnetic field energy density

The quantity intended here matches magnetic field energy density, whose unit is energy density=Jm3=kg m2 s−2m3=kg m−1 s−2\text{energy density} = \frac{J}{m^3} = \frac{kg\,m^2\,s^{-2}}{m^3}=kg\,m^{-1}\,s^{-2}energy density=m3J​=m3kgm2s−2​=kgm−1s−2 So, (c)→(iv)(c) \to (iv)(c)→(iv)


(d) η\etaη : coefficient of viscosity

Dynamic viscosity has SI unit Pa⋅s=(N/m2)⋅sPa\cdot s = (N/m^2)\cdot sPa⋅s=(N/m2)⋅s Now, Pa=Nm2=kg m s−2m2=kg m−1 s−2Pa = \frac{N}{m^2}=\frac{kg\,m\,s^{-2}}{m^2}=kg\,m^{-1}\,s^{-2}Pa=m2N​=m2kgms−2​=kgm−1s−2 Hence, [η]=kg m−1 s−2⋅s=kg m−1 s−1[\eta]=kg\,m^{-1}\,s^{-2}\cdot s = kg\,m^{-1}\,s^{-1}[η]=kgm−1s−2⋅s=kgm−1s−1 So, (d)→(i)(d) \to (i)(d)→(i)


  1. Final matching

(a)−(iii),(b)−(ii),(c)−(iv),(d)−(i)(a)-(iii),\quad (b)-(ii),\quad (c)-(iv),\quad (d)-(i)(a)−(iii),(b)−(ii),(c)−(iv),(d)−(i)

This corresponds to Option B.


  1. Comparison with stored correct answer

Stored correct answer = B

Our derived answer = B

So, the derived answer agrees with the stored answer.

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