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Units and Measurements question

2021 · 24 Feb · Shift 1 · Q59
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  5. /2021 · 24 Feb · Shift 1 · Q59

Units and Measurements question

2021 · 24 Feb · Shift 1 · Q59

JEE MainPhysicsUnits and MeasurementsMCQ+4 / −1
The work done by a gas molecule in an isolated system is given by, W=αβ2e−x2αkTW = \alpha {\beta ^2}{e^{ - {{{x^2}} \over {\alpha kT}}}}W=αβ2e−αkTx2​, where x is the displacement, k is the Boltzmann constant and T is the temperature. α\alphaα and β\betaβ are constants. Then the dimensions of β\betaβ will be :
  1. A
    [M0LT0][{M^0}L{T^0}][M0LT0]
  2. B
    [ML2T−2][M{L^2}{T^{ - 2}}][ML2T−2]
  3. C
    [MLT−2][ML{T^{ - 2}}][MLT−2]
  4. D
    [M2LT2][{M^2}L{T^2}][M2LT2]
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