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Simple Harmonic Motion question

2024 · 4 Apr · Shift 2 · Q89

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JEE Main
Physics
Simple Harmonic Motion
2024 · 4 Apr · Shift 2 · Q89

Simple Harmonic Motion question

2024 · 4 Apr · Shift 2 · Q89

JEE MainPhysicsSimple Harmonic MotionNumerical+4 / −1

The displacement of a particle executing SHM is given by

x=10 \sin \left(w t+\frac{\pi}{3}\right) m

. The time period of motion is

3.14 \mathrm{~s}

. The velocity of the particle at

t=0

is

\underline{\hspace{2cm}}

\mathrm{m} / \mathrm{s}

.

Numerical answer

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