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Simple Harmonic Motion question

2024 · 9 Apr · Shift 2 · Q86

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JEE Main
Physics
Simple Harmonic Motion
2024 · 9 Apr · Shift 2 · Q86

Simple Harmonic Motion question

2024 · 9 Apr · Shift 2 · Q86

JEE MainPhysicsSimple Harmonic MotionNumerical+4 / −1

A particle of mass

0.50 \mathrm{~kg}

executes simple harmonic motion under force

F=-50(\mathrm{Nm}^{-1}) x

. The time period of oscillation is

\frac{x}{35} s

. The value of

x

is

\underline{\hspace{2cm}}

. (Given

\pi=\frac{22}{7}

)

Numerical answer

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