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Simple Harmonic Motion question

2021 · 26 Aug · Shift 2 · Q68
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Simple Harmonic Motion question

2021 · 26 Aug · Shift 2 · Q68

JEE MainPhysicsSimple Harmonic MotionNumerical+4 / −1
Two simple harmonic motions are represented by the equations x1=5sin⁡(2πt+π4){x_1} = 5\sin \left( {2\pi t + {\pi \over 4}} \right)x1​=5sin(2πt+4π​) and x2=52(sin⁡2πt+cos⁡2πt){x_2} = 5\sqrt 2 (\sin 2\pi t + \cos 2\pi t)x2​=52​(sin2πt+cos2πt). The amplitude of second motion is ................ times the amplitude in first motion.
Numerical answer
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