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Simple Harmonic Motion question

2021 · 26 Feb · Shift 2 · Q68
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  5. /2021 · 26 Feb · Shift 2 · Q68

Simple Harmonic Motion question

2021 · 26 Feb · Shift 2 · Q68

JEE MainPhysicsSimple Harmonic MotionNumerical+4 / −1
A particle executes S.H.M. with amplitude 'a', and time period 'T'. The displacement of the particle when its speed is half of maximum speed is xa2{{\sqrt x a} \over 2}2x​a​. The value of x is ‾\underline{\hspace{2cm}}​.
Numerical answer
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