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Simple Harmonic Motion question

2016 · Shift 0 · Q54

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JEE Main
Physics
Simple Harmonic Motion
2016 · Shift 0 · Q54

Simple Harmonic Motion question

2016 · Shift 0 · Q54

JEE MainPhysicsSimple Harmonic MotionMCQ+4 / −1

A particle performs simple harmonic motion with amplitude

A.

Its speed is trebled at the instant that it is at a distance

{{2A} \over 3}

from equilibrium position. The new amplitude of the motion is:

A
$A\sqrt 3$
B
${{7A} \over 3}$
C
${A \over 3}\sqrt {41}$
D
$3A$

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