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Simple Harmonic Motion question

2015 · Shift 0 · Q60
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  5. /2015 · Shift 0 · Q60

Simple Harmonic Motion question

2015 · Shift 0 · Q60

JEE MainPhysicsSimple Harmonic MotionMCQ+4 / −1
A pendulum made of a uniform wire of cross sectional area AAA has time period T.T.T. When an additional mass MMM is added to its bob, the time period changes to TM.{T_{M.}}TM.​ If the Young's modulus of the material of the wire is YYY then 1Y{1 \over Y}Y1​ is equal to : (g=gravitationalaccelerationg=gravitationalaccelerationg=gravitationalacceleration)
  1. A
    [1−(TMT)2]AMg\left[ {1 - {{\left( {{{{T_M}} \over T}} \right)}^2}} \right]{A \over {Mg}}[1−(TTM​​)2]MgA​
  2. B
    [1−(TTM)2]AMg\left[ {1 - {{\left( {{T \over {{T_M}}}} \right)}^2}} \right]{A \over {Mg}}[1−(TM​T​)2]MgA​
  3. C
    [(TMT)2−1]AMg\left[ {{{\left( {{{{T_M}} \over T}} \right)}^2} - 1} \right]{A \over {Mg}}[(TTM​​)2−1]MgA​
  4. D
    [(TMT)2−1]MgA\left[ {{{\left( {{{{T_M}} \over T}} \right)}^2} - 1} \right]{{Mg} \over A}[(TTM​​)2−1]AMg​
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