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Simple Harmonic Motion question

2015 · Shift 0 · Q69
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  5. /2015 · Shift 0 · Q69

Simple Harmonic Motion question

2015 · Shift 0 · Q69

JEE MainPhysicsSimple Harmonic MotionMCQ+4 / −1
The period of oscillation of a simple pendulum is T=2πLgT = 2\pi \sqrt {{L \over g}}T=2πgL​​. Measured value of L is 20.0 cm known to 1 mm accuracy and time for 100 oscillations of the pendulum is found to be 90 s using wrist watch of 1 s resolution. The accuracy in the determination of g is:
  1. A
    1 %
  2. B
    5 %
  3. C
    2 %
  4. D
    3 %
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