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Simple Harmonic Motion question

2003 · Shift 0 · Q162

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JEE Main
Physics
Simple Harmonic Motion
2003 · Shift 0 · Q162

Simple Harmonic Motion question

2003 · Shift 0 · Q162

JEE MainPhysicsSimple Harmonic MotionMCQ+4 / −1

The displacement of particle varies according to the relation

x=4

\left( {\cos \,\pi t + \sin \,\pi t} \right).

The amplitude of the particle is

A
$-4$
B
$4$
C
$4\sqrt 2$
D
$8$

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