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Simple Harmonic Motion question

2025 · 3 Apr · Shift 1 · Q65
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  5. /2025 · 3 Apr · Shift 1 · Q65

Simple Harmonic Motion question

2025 · 3 Apr · Shift 1 · Q65

JEE MainPhysicsSimple Harmonic MotionMCQ+4 / −1
JEE Main 2025 (Online) 3rd April Morning Shift Physics - Simple Harmonic Motion Question 2 EnglishTwo blocks of masses mmm and M,(M>m)M,(M>m)M,(M>m), are placed on a frictionless table as shown in figure. A massless spring with spring constant k is attached with the lower block. If the system is slightly displaced and released, then ( μ=\mu=μ= coefficient of friction between the two blocks) A. The time period of small oscillation of the two blocks is T=2π(m+M)kT=2 \pi \sqrt{\frac{(m+M)}{k}}T=2πk(m+M)​​ B. The acceleration of the blocks is a=−kxM+ma=-\frac{k x}{M+m}a=−M+mkx​(x=x=x= displacement of the blocks from the mean position) C. The magnitude of the frictional force on the upper block is mμ∣x∣M+m\frac{m \mu|x|}{M+m}M+mmμ∣x∣​ D. The maximum amplitude of the upper block, if it does not slip, is μ(M+m)gk\frac{\mu(M+m) g}{k}kμ(M+m)g​ E. Maximum frictional force can be μ(M+m)g\mu(\mathrm{M}+\mathrm{m}) \mathrm{g}μ(M+m)g. Choose the correct answer from the options given below :
  1. A
    B, C, D Only
  2. B
    C, D, E Only
  3. C
    A, B, D Only
  4. D
    A, B, C Only
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