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Rotational Motion question

2025 · 7 Apr · Shift 2 · Q70
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Rotational Motion question

2025 · 7 Apr · Shift 2 · Q70

JEE MainPhysicsRotational MotionNumerical+4 / −1
M and R be the mass and radius of a disc. A small disc of radius R/3\mathrm{R} / 3R/3 is removed from the bigger disc as shown in figure. The moment of inertia of remaining part of bigger disc about an axis ABA BAB passing through the centre OOO and perpendicular to the plane of disc is 4xMR2\frac{4}{x} \mathrm{MR}^2x4​MR2. The value of xxx is ‾\underline{\hspace{2cm}}​. JEE Main 2025 (Online) 7th April Evening Shift Physics - Rotational Motion Question 6 English
Numerical answer
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