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Rotational Motion question

2025 · 23 Jan · Shift 1 · Q58
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  5. /2025 · 23 Jan · Shift 1 · Q58

Rotational Motion question

2025 · 23 Jan · Shift 1 · Q58

JEE MainPhysicsRotational MotionMCQ+4 / −1
A solid sphere of mass ' mmm' and radius 'rrr' is allowed to roll without slipping from the highest point of an inclined plane of length 'LLL' and makes an angle 30∘30^{\circ}30∘ with the horizontal. The speed of the particle at the bottom of the plane is v1v_1v1​. If the angle of inclination is increased to 45∘45^{\circ}45∘ while keeping LLL constant. Then the new speed of the sphere at the bottom of the plane is v2v_2v2​. The ratio v12:v22v_1^2: v_2^2v12​:v22​ is
  1. A
    1:31: 31:3
  2. B
    1:21: 21:2
  3. C
    1:21: \sqrt{2}1:2​
  4. D
    1:31: \sqrt{3}1:3​
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