A circular table is rotating with an angular velocity of $\omega \mathrm{~rad} / \mathrm{s}$ about its axis (see figure). There is a smooth groove along a radial direction on the table. A steel ball is gently placed at a distance of $1 \mathrm{~m}$ on the groove. All the surfaces are smooth. If the radius of the table is $3 \mathrm{~m}$, the radial velocity of the ball w.r.t. the table at the time ball leaves the table is $x \sqrt{2} \omega \mathrm{~m} / \mathrm{s}$, where the value of $x$ is $\underline{\hspace{2cm}}$.