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Properties of Matter question

2023 · 24 Jan · Shift 2 · Q61
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  5. /2023 · 24 Jan · Shift 2 · Q61

Properties of Matter question

2023 · 24 Jan · Shift 2 · Q61

JEE MainPhysicsProperties of MatterMCQ+4 / −1
The frequency (uuu) of an oscillating liquid drop may depend upon radius (rrr) of the drop, density (ρ\rhoρ) of liquid and the surface tension (s) of the liquid as u=raρbscu=r^a\rho^b s^cu=raρbsc. The values of a, b and c respectively are
  1. A
    (32,12,−12)\left( {{3 \over 2},{1 \over 2}, - {1 \over 2}} \right)(23​,21​,−21​)
  2. B
    (−32,−12,12)\left( { - {3 \over 2}, - {1 \over 2},{1 \over 2}} \right)(−23​,−21​,21​)
  3. C
    (32,−12,12)\left( {{3 \over 2}, - {1 \over 2},{1 \over 2}} \right)(23​,−21​,21​)
  4. D
    (−32,12,12)\left( { - {3 \over 2},{1 \over 2},{1 \over 2}} \right)(−23​,21​,21​)
View written solutionFree

Correct answer: B

  1. Assume the given relation

    u=raρbscu=r^a\rho^b s^cu=raρbsc

    where:

    • uuu = frequency
    • rrr = radius
    • ρ\rhoρ = density
    • sss = surface tension
  2. Write dimensions of each quantity

    • Frequency: [u]=T−1[u]=T^{-1}[u]=T−1
    • Radius: [r]=L[r]=L[r]=L
    • Density: [ρ]=ML−3[\rho]=ML^{-3}[ρ]=ML−3
    • Surface tension: [s]=forcelength=MLT−2L=MT−2[s]=\frac{\text{force}}{\text{length}}=\frac{MLT^{-2}}{L}=MT^{-2}[s]=lengthforce​=LMLT−2​=MT−2
  3. Substitute dimensions into the relation

    [u]=[r]a[ρ]b[s]c[u]=[r]^a[\rho]^b[s]^c[u]=[r]a[ρ]b[s]c

    T−1=La(ML−3)b(MT−2)cT^{-1}=L^a(ML^{-3})^b(MT^{-2})^cT−1=La(ML−3)b(MT−2)c

    Expanding:

    T−1=LaMbL−3bMcT−2cT^{-1}=L^a M^b L^{-3b} M^c T^{-2c}T−1=LaMbL−3bMcT−2c

    T−1=Mb+cLa−3bT−2cT^{-1}=M^{b+c}L^{a-3b}T^{-2c}T−1=Mb+cLa−3bT−2c

  4. Compare powers of MMM, LLL, and TTT

    For mass MMM: b+c=0b+c=0b+c=0

    For length LLL: a−3b=0a-3b=0a−3b=0

    For time TTT: −2c=−1-2c=-1−2c=−1 c=12c=\frac{1}{2}c=21​

  5. Find bbb and aaa

    From b+c=0b+c=0b+c=0, b=−12b=-\frac{1}{2}b=−21​

    From a−3b=0a-3b=0a−3b=0, a=3b=3(−12)=−32a=3b=3\left(-\frac{1}{2}\right)=-\frac{3}{2}a=3b=3(−21​)=−23​

  6. Final values

    a=−32,b=−12,c=12a=-\frac{3}{2},\quad b=-\frac{1}{2},\quad c=\frac{1}{2}a=−23​,b=−21​,c=21​

  7. Match with options

    This corresponds to:

    Option B

    (−32,−12,12)\left(-\frac{3}{2},-\frac{1}{2},\frac{1}{2}\right)(−23​,−21​,21​)

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