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Properties of Matter question

2023 · 29 Jan · Shift 1 · Q63
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  5. /2023 · 29 Jan · Shift 1 · Q63

Properties of Matter question

2023 · 29 Jan · Shift 1 · Q63

JEE MainPhysicsProperties of MatterMCQ+4 / −1
A bicycle tyre is filled with air having pressure of 270 kPa270 ~\mathrm{kPa}270 kPa at 27∘C27^{\circ} \mathrm{C}27∘C. The approximate pressure of the air in the tyre when the temperature increases to 36∘C36^{\circ} \mathrm{C}36∘C is
  1. A
    262 kPa
  2. B
    360 kPa
  3. C
    270 kPa
  4. D
    278 kPa
View written solutionFree

Correct answer: D

  1. Use Gay-Lussac’s law for a fixed mass of gas at constant volume:

P1T1=P2T2\frac{P_1}{T_1}=\frac{P_2}{T_2}T1​P1​​=T2​P2​​

Here,

  • Initial pressure: P1=270 kPaP_1=270\,\text{kPa}P1​=270kPa
  • Initial temperature: T1=27∘C=300 KT_1=27^\circ\text{C}=300\,\text{K}T1​=27∘C=300K
  • Final temperature: T2=36∘C=309 KT_2=36^\circ\text{C}=309\,\text{K}T2​=36∘C=309K
  1. Calculate final pressure:

P2=P1T2T1P_2=P_1\frac{T_2}{T_1}P2​=P1​T1​T2​​

P2=270×309300P_2=270\times \frac{309}{300}P2​=270×300309​

P2=270×1.03=278.1 kPaP_2=270\times 1.03=278.1\,\text{kPa}P2​=270×1.03=278.1kPa

  1. Approximate value:

P2≈278 kPaP_2\approx 278\,\text{kPa}P2​≈278kPa

  1. Evaluate options:
  • A: 262 kPa262\,\text{kPa}262kPa ❌
  • B: 360 kPa360\,\text{kPa}360kPa ❌
  • C: 270 kPa270\,\text{kPa}270kPa ❌
  • D: 278 kPa278\,\text{kPa}278kPa ✅

Therefore, the correct answer is D.

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