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Properties of Matter question

2005 · Shift 0 · Q144
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Properties of Matter question

2005 · Shift 0 · Q144

JEE MainPhysicsProperties of MatterMCQ+4 / −1
If SSS is stress and YYY is young's modulus of material of a wire, the energy stored in the wire per unit volume is
  1. A
    S22Y{{{S^2}} \over {2Y}}2YS2​
  2. B
    2S2Y2{S^2}Y2S2Y
  3. C
    S2Y{S \over {2Y}}2YS​
  4. D
    2YS2{{2Y} \over {{S^2}}}S22Y​
View written solutionFree

Correct answer: A

  1. Use the formula for elastic energy density

For a wire obeying Hooke’s law, the strain energy stored per unit volume is

u=12(stress)(strain)u = \frac{1}{2}(\text{stress})(\text{strain})u=21​(stress)(strain)

  1. Relate stress and strain using Young’s modulus

Young’s modulus is

Y=stressstrainY = \frac{\text{stress}}{\text{strain}}Y=strainstress​

So,

strain=stressY=SY\text{strain} = \frac{\text{stress}}{Y} = \frac{S}{Y}strain=Ystress​=YS​

  1. Substitute into the energy density formula

u=12⋅S⋅SYu = \frac{1}{2} \cdot S \cdot \frac{S}{Y}u=21​⋅S⋅YS​

u=S22Yu = \frac{S^2}{2Y}u=2YS2​

  1. Match with the options

Option A is

S22Y\frac{S^2}{2Y}2YS2​

So the correct answer is A.

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