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Motion in A Straight Line question

2022 · 29 Jul · Shift 1 · Q50
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  5. /2022 · 29 Jul · Shift 1 · Q50

Motion in A Straight Line question

2022 · 29 Jul · Shift 1 · Q50

JEE MainPhysicsMotion in A Straight LineMCQ+4 / −1
If t=x+4\mathrm{t}=\sqrt{x}+4t=x​+4, then (dx dt)t=4\left(\frac{\mathrm{d} x}{\mathrm{~d} t}\right)_{\mathrm{t}=4}( dtdx​)t=4​ is :
  1. A
    4
  2. B
    zero
  3. C
    8
  4. D
    16
View written solutionFree

Correct answer: B

  1. Given relation

    t=x+4t = \sqrt{x} + 4t=x​+4

    We need to find

    (dxdt)t=4\left(\frac{dx}{dt}\right)_{t=4}(dtdx​)t=4​

  2. Express xxx in terms of ttt

    From

    t−4=xt - 4 = \sqrt{x}t−4=x​

    squaring both sides,

    x=(t−4)2x = (t-4)^2x=(t−4)2

  3. Differentiate with respect to ttt

    dxdt=2(t−4)\frac{dx}{dt} = 2(t-4)dtdx​=2(t−4)

  4. Evaluate at t=4t=4t=4

    (dxdt)t=4=2(4−4)=0\left(\frac{dx}{dt}\right)_{t=4} = 2(4-4) = 0(dtdx​)t=4​=2(4−4)=0

  5. Check options

    • A: 444 ❌
    • B: 000 ✅
    • C: 888 ❌
    • D: 161616 ❌

Therefore, the correct answer is B: zero.

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