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Motion in A Plane question

2025 · 24 Jan · Shift 2 · Q67
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  5. /2025 · 24 Jan · Shift 2 · Q67

Motion in A Plane question

2025 · 24 Jan · Shift 2 · Q67

JEE MainPhysicsMotion in A PlaneMCQ+4 / −1
The position vector of a moving body at any instant of time is given as r→=(5t2i^−5tj^)m\overrightarrow{\mathrm{r}}=\left(5 \mathrm{t}^2 \hat{i}-5 \mathrm{t} \hat{j}\right) \mathrm{m}r=(5t2i^−5tj^​)m. The magnitude and direction of velocity at t=2st=2 st=2s is,
  1. A
    517 m/s5 \sqrt{17} \mathrm{~m} / \mathrm{s}517​ m/s, making an angle of tan⁡−14\tan ^{-1} 4tan−14 with - ve Y axis
  2. B
    515 m/s5 \sqrt{15} \mathrm{~m} / \mathrm{s}515​ m/s, making an angle of tan⁡−14\tan ^{-1} 4tan−14 with + ve XXX axis
  3. C
    517 m/s5 \sqrt{17} \mathrm{~m} / \mathrm{s}517​ m/s, making an angle of tan⁡−14\tan ^{-1} 4tan−14 with + ve XXX axis
  4. D
    515 m/s5 \sqrt{15} \mathrm{~m} / \mathrm{s}515​ m/s, making an angle of tan⁡−14\tan ^{-1} 4tan−14 with −-− ve YYY axis
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