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Motion in A Plane question

2020 · 8 Jan · Shift 1 · Q48
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Motion in A Plane question

2020 · 8 Jan · Shift 1 · Q48

JEE MainPhysicsMotion in A PlaneNumerical+4 / −1
A particle is moving along the x-axis with its coordinate with the time 't' given be x(t) = 10 + 8t – 3t2. Another particle is moving the y-axis with its coordinate as a function of time given by y(t) = 5 – 8t3. At t = 1s, the speed of the second particle as measured in the frame of the first particle is given as v\sqrt vv​. Then v (in m/s) is ‾\underline{\hspace{2cm}}​.
Numerical answer
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