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Magnetics question

2025 · 29 Jan · Shift 2 · Q75
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Magnetics question

2025 · 29 Jan · Shift 2 · Q75

JEE MainPhysicsMagneticsNumerical+4 / −1
The magnetic field inside a 200 turns solenoid of radius 10 cm is 2.9×10−4 Tesla2.9 \times 10^{-4} ~\mathrm{Tesla}2.9×10−4 Tesla. If the solenoid carries a current of 0.29 A , then the length of the solenoid is ‾πcm\underline{\hspace{2cm}}\pi \mathrm{cm}​πcm.
Numerical answer
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