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Magnetics question

2025 · 3 Apr · Shift 1 · Q72
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Magnetics question

2025 · 3 Apr · Shift 1 · Q72

JEE MainPhysicsMagneticsNumerical+4 / −1
A loop ABCDA , carrying current I=12 A\mathrm{I}=12 \mathrm{~A}I=12 A, is placed in a plane, consists of two semi-circular segments of radius R1=6π mR_1=6 \pi \mathrm{~m}R1​=6π m and R2=4π m\mathrm{R}_2=4 \pi \mathrm{~m}R2​=4π m. The magnitude of the resultant magnetic field at center O is k×10−7 T\mathrm{k} \times 10^{-7} \mathrm{~T}k×10−7 T. The value of k is ‾\underline{\hspace{2cm}}​. ( Given μ0=4π×10−7TmA−1\mu_0=4 \pi \times 10^{-7} \mathrm{Tm} \mathrm{A}^{-1}μ0​=4π×10−7TmA−1 ) JEE Main 2025 (Online) 3rd April Morning Shift Physics - Magnetic Effect of Current Question 4 English
Numerical answer
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