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Magnetics question

2017 · 8 Apr · Shift 1 · Q57
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Magnetics question

2017 · 8 Apr · Shift 1 · Q57

JEE MainPhysicsMagneticsMCQ+4 / −1
In a certain region static electric and magnetic fields exist. The magnetic field is given by B→=B0(i^+2j^−4k^)\overrightarrow B = {B_0}\left( {\widehat i + 2\widehat j - 4\widehat k} \right)B=B0​(i+2j​−4k). If a test charge moving with a velocity υ→=υ0(3i^−j^+2k^)\overrightarrow \upsilon = {\upsilon _0}\left( {3\widehat i - \widehat j + 2\widehat k} \right)υ=υ0​(3i−j​+2k) experiences no force in that region, then the electric field in the region, in SI units, is :
  1. A
    E→=−υ0 B0(3i^−2j^−4k^)\overrightarrow E = - {\upsilon _0}\,{B_0}\left( {3\widehat i - 2\widehat j - 4\widehat k} \right)E=−υ0​B0​(3i−2j​−4k)
  2. B
    E→=−υ0 B0(i^+j^+7k^)\overrightarrow E = - {\upsilon _0}\,{B_0}\left( {\widehat i + \widehat j + 7\widehat k} \right)E=−υ0​B0​(i+j​+7k)
  3. C
    E→=υ0 B0(14j^+7k^)\overrightarrow E = {\upsilon _0}\,{B_0}\left( {14\widehat j + 7\widehat k} \right)E=υ0​B0​(14j​+7k)
  4. D
    E→=−υ0 B0(14j^+7k^)\overrightarrow E = - {\upsilon _0}\,{B_0}\left( {14\widehat j + 7\widehat k} \right)E=−υ0​B0​(14j​+7k)
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