JEE MainPhysicsMagnetic Properties of MatterNumerical+4 / −1
The current required to be passed through a solenoid of 15 cm length and 60 turns in order of demagnetise a bar magnet of magnetic intensity is A.
Numerical answer
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Correct answer: 6
- Use the relation between magnetic field strength and solenoid current
For a solenoid, the magnetic field strength (magnetising field) is
where:
- = magnetic field intensity in
- = number of turns
- = length of solenoid
- = current
To demagnetise the bar magnet, the solenoid must produce a magnetising field equal in magnitude to the magnetic intensity of the magnet.
So,
- Substitute the given values
Given:
Using
we get
- Simplify
So,
- Final answer
- Comparison with stored answer
Stored correct answer =
Our derived answer also is , so they agree.
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