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Magnetic Properties of Matter question

2023 · 25 Jan · Shift 1 · Q58
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  5. /2023 · 25 Jan · Shift 1 · Q58

Magnetic Properties of Matter question

2023 · 25 Jan · Shift 1 · Q58

JEE MainPhysicsMagnetic Properties of MatterMCQ+4 / −1
A solenoid of 1200 turns is wound uniformly in a single layer on a glass tube 2 m long and 0.2 m in diameter. The magnetic intensity at the center of the solenoid when a current of 2 A flows through it is :
  1. A
    1 A m−1\mathrm{1~A~m^{-1}}1 A m−1
  2. B
    2.4×10−3 A m−1\mathrm{2.4\times10^{-3}~A~m^{-1}}2.4×10−3 A m−1
  3. C
    1.2×103 A m−1\mathrm{1.2\times10^{3}~A~m^{-1}}1.2×103 A m−1
  4. D
    2.4×103 A m−1\mathrm{2.4\times10^{3}~A~m^{-1}}2.4×103 A m−1
View written solutionFree

Correct answer: C

  1. Magnetic intensity inside a solenoid

For a long solenoid, the magnetic intensity is

H=nI=NLIH = nI = \frac{N}{L}IH=nI=LN​I

where:

  • N=1200N = 1200N=1200 is the number of turns,
  • L=2 mL = 2\,\text{m}L=2m is the length of the solenoid,
  • I=2 AI = 2\,\text{A}I=2A is the current.
  1. Compute turns per unit length

n=NL=12002=600 turns m−1n = \frac{N}{L} = \frac{1200}{2} = 600\,\text{turns m}^{-1}n=LN​=21200​=600turns m−1

  1. Compute magnetic intensity

H=nI=600×2=1200 A m−1H = nI = 600 \times 2 = 1200\,\text{A m}^{-1}H=nI=600×2=1200A m−1

Thus,

H=1.2×103 A m−1H = 1.2 \times 10^3\,\text{A m}^{-1}H=1.2×103A m−1

  1. Match with options
  • A: 1 A m−11\,\text{A m}^{-1}1A m−1 — incorrect
  • B: 2.4×10−3 A m−12.4\times10^{-3}\,\text{A m}^{-1}2.4×10−3A m−1 — incorrect
  • C: 1.2×103 A m−11.2\times10^3\,\text{A m}^{-1}1.2×103A m−1 — correct
  • D: 2.4×103 A m−12.4\times10^3\,\text{A m}^{-1}2.4×103A m−1 — incorrect

Hence, the correct option is C.

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