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Laws of Motion question

2025 · 8 Apr · Shift 2 · Q68
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  5. /2025 · 8 Apr · Shift 2 · Q68

Laws of Motion question

2025 · 8 Apr · Shift 2 · Q68

JEE MainPhysicsLaws of MotionMCQ+4 / −1
A body of mass 2 kg moving with velocity of v⃗in=3i^+4j^ ms−1\vec{v}_{in} = 3 \hat{i} + 4 \hat{j} \text{ ms}^{-1}vin​=3i^+4j^​ ms−1 enters into a constant force field of 6N directed along positive z-axis. If the body remains in the field for a period of 53\frac{5}{3}35​ seconds, then velocity of the body when it emerges from force field is.
  1. A
    3i^+4j^+5k^3\hat{i} + 4\hat{j} + \sqrt{5} \hat{k}3i^+4j^​+5​k^
  2. B
    4i^+3j^+5k^4\hat{i} + 3\hat{j} + 5\hat{k}4i^+3j^​+5k^
  3. C
    3i^+4j^−5k^3\hat{i} + 4\hat{j} - 5\hat{k}3i^+4j^​−5k^
  4. D
    3i^+4j^+5k^3\hat{i} + 4\hat{j} + 5\hat{k}3i^+4j^​+5k^
View written solutionFree

Correct answer: D

  1. Given data
  • Mass of body: m=2 kgm = 2\,\text{kg}m=2kg
  • Initial velocity: v⃗in=3i^+4j^  m s−1\vec{v}_{in} = 3\hat{i} + 4\hat{j}\;\text{m s}^{-1}vin​=3i^+4j^​m s−1
  • Force acting on body: F⃗=6k^  N\vec{F} = 6\hat{k}\;\text{N}F=6k^N
  • Time spent in field: t=53  st = \frac{5}{3}\;\text{s}t=35​s
  1. Find acceleration

Using Newton's second law, a⃗=F⃗m=6k^2=3k^  m s−2\vec{a} = \frac{\vec{F}}{m} = \frac{6\hat{k}}{2} = 3\hat{k}\;\text{m s}^{-2}a=mF​=26k^​=3k^m s−2

So the acceleration is only along the positive zzz-axis.

  1. Find change in velocity

Change in velocity is Δv⃗=a⃗t=3k^×53=5k^  m s−1\Delta \vec{v} = \vec{a}t = 3\hat{k} \times \frac{5}{3} = 5\hat{k}\;\text{m s}^{-1}Δv=at=3k^×35​=5k^m s−1

  1. Find final velocity

v⃗out=v⃗in+Δv⃗\vec{v}_{out} = \vec{v}_{in} + \Delta \vec{v}vout​=vin​+Δv

v⃗out=(3i^+4j^)+5k^\vec{v}_{out} = (3\hat{i} + 4\hat{j}) + 5\hat{k}vout​=(3i^+4j^​)+5k^

v⃗out=3i^+4j^+5k^  m s−1\boxed{\vec{v}_{out} = 3\hat{i} + 4\hat{j} + 5\hat{k}\;\text{m s}^{-1}}vout​=3i^+4j^​+5k^m s−1​

  1. Check options
  • A: 3i^+4j^+5k^3\hat{i} + 4\hat{j} + \sqrt{5}\hat{k}3i^+4j^​+5​k^ ❌
  • B: 4i^+3j^+5k^4\hat{i} + 3\hat{j} + 5\hat{k}4i^+3j^​+5k^ ❌
  • C: 3i^+4j^−5k^3\hat{i} + 4\hat{j} - 5\hat{k}3i^+4j^​−5k^ ❌
  • D: 3i^+4j^+5k^3\hat{i} + 4\hat{j} + 5\hat{k}3i^+4j^​+5k^ ✅

Therefore, the correct option is: D\boxed{\text{D}}D​

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