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Laws of Motion question

2024 · 1 Feb · Shift 2 · Q62
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  5. /2024 · 1 Feb · Shift 2 · Q62

Laws of Motion question

2024 · 1 Feb · Shift 2 · Q62

JEE MainPhysicsLaws of MotionMCQ+4 / −1
A body of mass 4 kg4 \mathrm{~kg}4 kg experiences two forces F⃗1=5i^+8j^+7k^\vec{F}_1=5 \hat{i}+8 \hat{j}+7 \hat{k}F1​=5i^+8j^​+7k^ and F→2=3i^−4j^−3k^\overrightarrow{\mathrm{F}}_2=3 \hat{i}-4 \hat{j}-3 \hat{k}F2​=3i^−4j^​−3k^. The acceleration acting on the body is :
  1. A
    2i^+j^+k^2 \hat{i}+\hat{j}+\hat{k}2i^+j^​+k^
  2. B
    4i^+2j^+2k^4 \hat{i}+2 \hat{j}+2 \hat{k}4i^+2j^​+2k^
  3. C
    −2i^−j^−k^-2 \hat{i}-\hat{j}-\hat{k}−2i^−j^​−k^
  4. D
    2i^+3j^+3k^2 \hat{i}+3 \hat{j}+3 \hat{k}2i^+3j^​+3k^
View written solutionFree

Correct answer: A

  1. Given data
  • Mass of the body: m=4 kgm=4\,\text{kg}m=4kg
  • Forces: F⃗1=5i^+8j^+7k^\vec F_1=5\hat i+8\hat j+7\hat kF1​=5i^+8j^​+7k^ F⃗2=3i^−4j^−3k^\vec F_2=3\hat i-4\hat j-3\hat kF2​=3i^−4j^​−3k^
  1. Find the net force

The resultant force is: F⃗=F⃗1+F⃗2\vec F=\vec F_1+\vec F_2F=F1​+F2​

So, F⃗=(5+3)i^+(8−4)j^+(7−3)k^\vec F=(5+3)\hat i+(8-4)\hat j+(7-3)\hat kF=(5+3)i^+(8−4)j^​+(7−3)k^ F⃗=8i^+4j^+4k^\vec F=8\hat i+4\hat j+4\hat kF=8i^+4j^​+4k^

  1. Use Newton's second law

F⃗=ma⃗\vec F=m\vec aF=ma

Therefore, a⃗=F⃗m\vec a=\frac{\vec F}{m}a=mF​

a⃗=8i^+4j^+4k^4\vec a=\frac{8\hat i+4\hat j+4\hat k}{4}a=48i^+4j^​+4k^​

a⃗=2i^+j^+k^\vec a=2\hat i+\hat j+\hat ka=2i^+j^​+k^

  1. Match with the options
  • A: 2i^+j^+k^2\hat i+\hat j+\hat k2i^+j^​+k^ ✓
  • B: 4i^+2j^+2k^4\hat i+2\hat j+2\hat k4i^+2j^​+2k^ ✗
  • C: −2i^−j^−k^-2\hat i-\hat j-\hat k−2i^−j^​−k^ ✗
  • D: 2i^+3j^+3k^2\hat i+3\hat j+3\hat k2i^+3j^​+3k^ ✗

Hence, the correct answer is Option A.

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