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Laws of Motion question

2025 · 3 Apr · Shift 2 · Q61
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Laws of Motion question

2025 · 3 Apr · Shift 2 · Q61

JEE MainPhysicsLaws of MotionMCQ+4 / −1
A block of mass 1 kg , moving along xxx with speed vi=10 m/sv_i=10 \mathrm{~m} / \mathrm{s}vi​=10 m/s enters a rough region ranging from x=0.1 mx=0.1 \mathrm{~m}x=0.1 m to x=1.9 mx=1.9 \mathrm{~m}x=1.9 m. The retarding force acting on the block in this range is Fr=−krN\mathrm{F}_{\mathrm{r}}=-\mathrm{kr} \mathrm{N}Fr​=−krN, with k =10 N/m=10 \mathrm{~N} / \mathrm{m}=10 N/m. Then the final speed of the block as it crosses rough region is.
  1. A
    4 m/s4 \mathrm{~m} / \mathrm{s}4 m/s
  2. B
    10 m/s10 \mathrm{~m} / \mathrm{s}10 m/s
  3. C
    8 m/s8 \mathrm{~m} / \mathrm{s}8 m/s
  4. D
    6 m/s6 \mathrm{~m} / \mathrm{s}6 m/s
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