Doubts
Sign in
12thPass logo
New chatPYQ LibraryDoubtsRank report
Sign in to see Recents
Sign in to save progress →
Doubts
Sign in

Laws of Motion question

2024 · 31 Jan · Shift 2 · Q66
Guest · try one question or challengeGuest · try one question or challenge
  1. PYQ Library
  2. /JEE Main
  3. /Physics
  4. /Laws of Motion
  5. /2024 · 31 Jan · Shift 2 · Q66

Laws of Motion question

2024 · 31 Jan · Shift 2 · Q66

JEE MainPhysicsLaws of MotionMCQ+4 / −1
JEE Main 2024 (Online) 31st January Evening Shift Physics - Laws of Motion Question 26 English A block of mass 5 kg5 \mathrm{~kg}5 kg is placed on a rough inclined surface as shown in the figure. If F1→\overrightarrow{F_1}F1​​ is the force required to just move the block up the inclined plane and F2→\overrightarrow{F_2}F2​​ is the force required to just prevent the block from sliding down, then the value of ∣F1→∣−∣F2→∣\left|\overrightarrow{F_1}\right|-\left|\overrightarrow{F_2}\right|​F1​​​−​F2​​​ is : [Use g=10 m/s2]\left.\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2\right]g=10 m/s2]
  1. A
    53N5 \sqrt{3} N53​N
  2. B
    532N\frac{5 \sqrt{3}}{2} N253​​N
  3. C
    10 N10 \mathrm{~N}10 N
  4. D
    253N25 \sqrt{3} N253​N
PreviousNext

More from Laws of Motion

  • A light string passing over a smooth light fixed pulley connects two blocks of masses m1​ and m2​. If the acceleration of the system is g/8, then the ratio of masses is: Includes diagram2024 · MCQ
  • A block of mass 5 kg is placed at rest on a table of rough surface. Now, if a force of 30 N is applied in the direction parallel to surface of the table, the block slides through a distance of 50 m in an…2023 · MCQ
  • As shown in the figure a block of mass 10 kg lying on a horizontal surface is pulled by a force F acting at an angle 30∘, with horizontal. For μs​=0.25, the block will just start to move for the value of F : [Given g=10 ms−2… Includes diagram2023 · MCQ
  • Figures (a), (b), (c) and (d) show variation of force with time. The impulse is highest in figure. Includes diagram2023 · MCQ
  • At any instant the velocity of a particle of mass 500 g is (2ti^+3t2j^​)ms−1. If the force acting on the particle at t=1 s is (i^+xj^​)N. Then the…2023 · MCQ
  • A body of mass 500 g moves along x-axis such that it's velocity varies with displacement x according to the relation v=10x​ m/s the force acting on the body is:-2023 · MCQ
  • Three forces F1​=10 N,F2​=8 N, F3​=6 N are acting on a particle of mass 5 kg. The forces F2​ and F3​ are applied perpendicularly so that particle…2023 · MCQ
  • The position vector of a particle related to time t is given by r=(10ti^+15t2j^​+7k^)m The direction of net force experienced by the particle is :2023 · MCQ