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Laws of Motion question

2024 · 9 Apr · Shift 2 · Q79

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Laws of Motion
2024 · 9 Apr · Shift 2 · Q79

Laws of Motion question

2024 · 9 Apr · Shift 2 · Q79

JEE MainPhysicsLaws of MotionMCQ+4 / −1

A

1 \mathrm{~kg}

mass is suspended from the ceiling by a rope of length

4 \mathrm{~m}

. A horizontal force '

F

' is applied at the mid point of the rope so that the rope makes an angle of

45^{\circ}

with respect to the vertical axis as shown in figure. The magnitude of

F

is : (Assume that the system is in equilibrium and

g=10 \mathrm{~m} / \mathrm{s}^2

)

JEE Main 2024 (Online) 9th April Evening Shift Physics - Laws of Motion Question 21 English

A
1 N
B
10 N
C
$\frac{10}{\sqrt{2}} N$
D
$\frac{1}{10 \times \sqrt{2}} N$

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