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Laws of Motion question

2024 · 5 Apr · Shift 2 · Q63

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JEE Main
Physics
Laws of Motion
2024 · 5 Apr · Shift 2 · Q63

Laws of Motion question

2024 · 5 Apr · Shift 2 · Q63

JEE MainPhysicsLaws of MotionMCQ+4 / −1

A particle moves in

x

-

y

plane under the influence of a force

\vec{F}

such that its linear momentum is

\overrightarrow{\mathrm{p}}(\mathrm{t})=\hat{i} \cos (\mathrm{kt})-\hat{j} \sin (\mathrm{kt})

. If

\mathrm{k}

is constant, the angle between

\overrightarrow{\mathrm{F}}

and

\overrightarrow{\mathrm{p}}

will be :

A
$\frac{\pi}{2}$
B
$\frac{\pi}{3}$
C
$\frac{\pi}{4}$
D
$\frac{\pi}{6}$

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