JEE MainPhysicsLaws of MotionMCQ+4 / −1
A mass of 10 kg is suspended vertically by a rope from the roof. When a horizontal force is applied on the rope at some point. the rope deviated at an angle of 45o at the roof point. If the suspended mass is at equilibrium, the magnitude of the force applied is (g = 10 ms 2
- A200 N
- B140 N
- C70 N
- D100 N
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