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Heat and Thermodynamics question

2025 · 7 Apr · Shift 2 · Q57
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  5. /2025 · 7 Apr · Shift 2 · Q57

Heat and Thermodynamics question

2025 · 7 Apr · Shift 2 · Q57

JEE MainPhysicsHeat and ThermodynamicsMCQ+4 / −1
The helium and argon are put in the flask at the same room temperature (300 K). The ratio of average kinetic energies (per molecule) of helium and argon is: (Give: Molar mass of helium = 4 g/mol, Molar mass of argon = 40 g/mol)
  1. A
    1 : 10\sqrt{10}10​
  2. B
    10 : 1
  3. C
    1 : 10
  4. D
    1 : 1
View written solutionFree

Correct answer: D

  1. Average kinetic energy of a gas molecule

    For any ideal gas, the average translational kinetic energy per molecule is Kˉ=32kT\bar{K} = \frac{3}{2}kTKˉ=23​kT where:

    • kkk = Boltzmann constant
    • TTT = absolute temperature
  2. Compare helium and argon

    Both helium and argon are at the same temperature: T=300 KT = 300\,\text{K}T=300K

    Therefore, KˉHe=32kT\bar{K}_{\text{He}} = \frac{3}{2}kTKˉHe​=23​kT and KˉAr=32kT\bar{K}_{\text{Ar}} = \frac{3}{2}kTKˉAr​=23​kT

  3. Take the ratio

    KˉHe:KˉAr=32kT:32kT=1:1\bar{K}_{\text{He}} : \bar{K}_{\text{Ar}} = \frac{3}{2}kT : \frac{3}{2}kT = 1:1KˉHe​:KˉAr​=23​kT:23​kT=1:1

  4. Important concept

    Average kinetic energy depends only on temperature, not on molar mass. The given molar masses are irrelevant for this question.

  5. Check options

    • A: 1:101 : \sqrt{10}1:10​ →\rightarrow→ incorrect
    • B: 10:110 : 110:1 →\rightarrow→ incorrect
    • C: 1:101 : 101:10 →\rightarrow→ incorrect
    • D: 1:11 : 11:1 →\rightarrow→ correct

Therefore, the correct option is D.

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