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Heat and Thermodynamics question

2025 · 7 Apr · Shift 2 · Q71

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JEE Main
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Heat and Thermodynamics
2025 · 7 Apr · Shift 2 · Q71

Heat and Thermodynamics question

2025 · 7 Apr · Shift 2 · Q71

JEE MainPhysicsHeat and ThermodynamicsNumerical+4 / −1

Two cylindrical rods A and B made of different materials, are joined in a straight line. The ratios of lengths, radii and thermal conductivites of these rods are:

\frac{\mathrm{L}_{\mathrm{A}}}{\mathrm{L}_{\mathrm{B}}}=\frac{1}{2}, \frac{\mathrm{r}_{\mathrm{A}}}{\mathrm{r}_{\mathrm{B}}}=2

and

\frac{\mathrm{K}_{\mathrm{A}}}{\mathrm{K}_{\mathrm{B}}}=\frac{1}{2}

. The free ends of rods A and B are maintained at 400 K , 200 K , respectively. The temperature of rods interface is

\underline{\hspace{2cm}}K

, when equilibrium is established.

Numerical answer

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