JEE MainPhysicsGeometrical OpticsMCQ+4 / −1
A symmetric thin biconvex lens is cut into four equal parts by two planes and as shown in figure. If the power of original lens is 4D then the power of a part of the divided lens is 

- A2D
- B8D
- C4D
- DD
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Correct answer: C: 4D
- Power of a thin lens
For a thin lens in air, where is the power.
For a symmetric biconvex lens,
So,
= (\mu-1)\left(\frac{2}{R}\right)$$ Given original power, $$P=4\,\text{D}$$ --- 2. **Effect of cutting the lens** The lens is cut into four equal parts by two planes as shown. Such cutting changes the **aperture/size** of each part, but does not change the radii of curvature of the refracting surfaces for each piece. Hence, the focal length and therefore the **power of each part remain unchanged**. So each part has the same power as the original lens: $$P' = 4\,\text{D}$$ --- 3. **Check the options** - A: $2\,\text{D}$ ❌ - B: $8\,\text{D}$ ❌ - C: $4\,\text{D}$ ✅ - D: $1\,\text{D}$ ❌ Thus, the correct option is: $$\boxed{4\,\text{D}}$$ --- 4. **Comparison with stored answer** Stored correct answer: **A = $2\,\text{D}$** My derived answer is **C = $4\,\text{D}$**. The stored answer appears incorrect, because cutting a thin lens into pieces by planes containing/parallel to the principal axis changes only the aperture, not the curvatures, so the power of each piece remains the same as the original lens.More from Geometrical Optics
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