JEE MainPhysicsGeometrical OpticsMCQ+4 / −1
A plano-convex lens having radius of curvature of first surface 2 cm exhibits focal length of in air. Another plano-convex lens with first surface radius of curvature 3 cm has focal length of when it is immersed in a liquid of refractive index 1.2. If both the lenses are made of same glass of refractive index 1.5 , the ratio of and will be
- A
- B
- C
- D
View written solutionFree
Correct answer: B
- Use lens maker formula
For a thin lens in a medium of refractive index :
where is refractive index of lens material.
For a plano-convex lens, one surface is plane, so its radius is .
Thus,
will reduce to just the curved surface contribution in magnitude.
- First lens in air
Given:
- (air)
- curved surface radius
So,
Hence,
- Second lens immersed in liquid
Given:
- curved surface radius
Relative refractive index of lens w.r.t. liquid:
Therefore,
So,
- Find the ratio
- Check options
- A: ❌
- B: ✅
- C: ❌
- D: ❌
So the correct option is B.
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