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Geometrical Optics question

2019 · 9 Jan · Shift 2 · Q59
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Geometrical Optics question

2019 · 9 Jan · Shift 2 · Q59

JEE MainPhysicsGeometrical OpticsMCQ+4 / −1
Two plane mirrors are inclined to each other such that a ray of light incident on the first mirror (M1) and parallel to the second mirror (M2) is finally reflected from the second mirror (M2) parallel to the first mirror (M1). The angle between the two mirrors will be :
  1. A
    45o
  2. B
    60o
  3. C
    75o
  4. D
    90o
View written solutionFree

Correct answer: B

  1. Set up the geometry

Let the angle between the two plane mirrors M1M_1M1​ and M2M_2M2​ be θ\thetaθ.

The incident ray is:

  • incident on M1M_1M1​
  • parallel to M2M_2M2​

After reflection from M2M_2M2​, the final ray is:

  • parallel to M1M_1M1​

  1. Use the property of successive reflections

When a ray is reflected successively from two plane mirrors inclined at an angle θ\thetaθ, the net deviation in the direction of the ray is:

2θ2\theta2θ

That is, the angle between the initial direction and the final direction is 2θ2\theta2θ.


  1. Find the angle between initial and final rays

Initially, the ray is parallel to M2M_2M2​. Finally, the ray is parallel to M1M_1M1​.

Therefore, the angle between the initial and final directions is exactly the angle between the mirrors:

θ\thetaθ

But from the two-reflection result, this angle must also equal:

2θ2\theta2θ

This seems contradictory unless we interpret the directions carefully.

Since the ray changes side after reflection, the actual angle between the directed initial and final rays is the supplement of θ\thetaθ:

180∘−θ180^\circ - \theta180∘−θ

Hence,

2θ=180∘−θ2\theta = 180^\circ - \theta2θ=180∘−θ

3θ=180∘3\theta = 180^\circ3θ=180∘

θ=60∘\theta = 60^\circθ=60∘


  1. Check with options
  • A: 45∘45^\circ45∘
  • B: 60∘60^\circ60∘ ✅
  • C: 75∘75^\circ75∘
  • D: 90∘90^\circ90∘

So the correct answer is:

60∘\boxed{60^\circ}60∘​

Therefore, Option B is correct.

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