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Electrostatics question

2024 · 31 Jan · Shift 2 · Q88
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Electrostatics question

2024 · 31 Jan · Shift 2 · Q88

JEE MainPhysicsElectrostaticsNumerical+4 / −1
The distance between charges +q+q+q and −q-q−q is 2l2 l2l and between +2q+2 q+2q and −2q-2 q−2q is 4l4 l4l. The electrostatic potential at point PPP at a distance rrr from center OOO is −α[qlr2]×109 V-\alpha\left[\frac{q l}{r^2}\right] \times 10^9 \mathrm{~V}−α[r2ql​]×109 V, where the value of α\alphaα is ‾\underline{\hspace{2cm}}​. (Use 14πε0=9×109 Nm2C−2\frac{1}{4 \pi \varepsilon_0}=9 \times 10^9 \mathrm{~Nm}^2 \mathrm{C}^{-2}4πε0​1​=9×109 Nm2C−2) JEE Main 2024 (Online) 31st January Evening Shift Physics - Electrostatics Question 61 English
Numerical answer
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