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Electrostatics question

2023 · 8 Apr · Shift 2 · Q52
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Electrostatics question

2023 · 8 Apr · Shift 2 · Q52

JEE MainPhysicsElectrostaticsMCQ+4 / −1
Electric potential at a point 'P\mathrm{P}P' due to a point charge of 5×10−9C5 \times 10^{-9} \mathrm{C}5×10−9C is 50 V50 \mathrm{~V}50 V. The distance of 'P\mathrm{P}P' from the point charge is: (Assume, 14πε0=9×10+9 Nm2C−2\frac{1}{4 \pi \varepsilon_{0}}=9 \times 10^{+9} ~\mathrm{Nm}^{2} \mathrm{C}^{-2}4πε0​1​=9×10+9 Nm2C−2 )
  1. A
    0.9 cm
  2. B
    90 cm
  3. C
    3 cm
  4. D
    9 cm
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