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Electrostatics question

2021 · 26 Feb · Shift 1 · Q56
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  5. /2021 · 26 Feb · Shift 1 · Q56

Electrostatics question

2021 · 26 Feb · Shift 1 · Q56

JEE MainPhysicsElectrostaticsMCQ+4 / −1
Find the electric field at point P (as shown in figure) on the perpendicular bisector of a uniformly charged thin wire of length L carrying a charge Q. The distance of the point P from the centre of the rod is a = 32L{{\sqrt 3 } \over 2}L23​​L. JEE Main 2021 (Online) 26th February Morning Shift Physics - Electrostatics Question 154 English
  1. A
    Q4πε0L2{Q \over {4\pi {\varepsilon _0}{L^2}}}4πε0​L2Q​
  2. B
    Q3πε0L2{Q \over {3\pi {\varepsilon _0}{L^2}}}3πε0​L2Q​
  3. C
    Q23πε0L2{Q \over {2\sqrt 3 \pi {\varepsilon _0}{L^2}}}23​πε0​L2Q​
  4. D
    3Q4πε0L2{{\sqrt 3 Q} \over {4\pi {\varepsilon _0}{L^2}}}4πε0​L23​Q​
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