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Electrostatics question

2021 · 27 Aug · Shift 2 · Q58
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Electrostatics question

2021 · 27 Aug · Shift 2 · Q58

JEE MainPhysicsElectrostaticsMCQ+4 / −1
Figure shows a rod AB, which is bent in a 120 ∘^\circ∘ circular arc of radius R. A charge (−-− Q) is uniformly distributed over rod AB. What is the electric field E→\overrightarrow EE at the centre of curvature O ? JEE Main 2021 (Online) 27th August Evening Shift Physics - Electrostatics Question 135 English
  1. A
    33Q8πε0R2(i^){{3\sqrt 3 Q} \over {8\pi {\varepsilon _0}{R^2}}}(\widehat i)8πε0​R233​Q​(i)
  2. B
    33Q8π2ε0R2(i^){{3\sqrt 3 Q} \over {8{\pi ^2}{\varepsilon _0}{R^2}}}(\widehat i)8π2ε0​R233​Q​(i)
  3. C
    33Q16π2ε0R2(i^){{3\sqrt 3 Q} \over {16{\pi ^2}{\varepsilon _0}{R^2}}}(\widehat i)16π2ε0​R233​Q​(i)
  4. D
    33Q8π2ε0R2(−i^){{3\sqrt 3 Q} \over {8{\pi ^2}{\varepsilon _0}{R^2}}}( - \widehat i)8π2ε0​R233​Q​(−i)
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