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Electrostatics question

2021 · 25 Feb · Shift 2 · Q72
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Electrostatics question

2021 · 25 Feb · Shift 2 · Q72

JEE MainPhysicsElectrostaticsNumerical+4 / −1
Two identical conducting spheres with negligible volume have 2.1 nC and −-− 0.1 nC charges, respectively. They are brought into contact and then separated by a distance of 0.5 m. The electrostatic force acting between the spheres is ‾×\underline{\hspace{2cm}}\times​× 10 −-− 9 N. [Given : 4πε0=19×1094\pi {\varepsilon _0} = {1 \over {9 \times {{10}^9}}}4πε0​=9×1091​ SI unit]
Numerical answer
View written solutionFree

Correct answer: 36

  1. Initial charges on identical conducting spheres

Given:

  • q1=2.1 nCq_1 = 2.1\,\text{nC}q1​=2.1nC
  • q2=−0.1 nCq_2 = -0.1\,\text{nC}q2​=−0.1nC

When two identical conducting spheres are brought into contact, the total charge gets equally distributed.

So total charge, qtotal=2.1+(−0.1)=2.0 nCq_{\text{total}} = 2.1 + (-0.1) = 2.0\,\text{nC}qtotal​=2.1+(−0.1)=2.0nC

Hence charge on each sphere after contact: q=2.02=1.0 nCq = \frac{2.0}{2} = 1.0\,\text{nC}q=22.0​=1.0nC

Thus after separation: q1′=q2′=1.0 nC=1.0×10−9 Cq_1' = q_2' = 1.0\,\text{nC} = 1.0 \times 10^{-9}\,\text{C}q1′​=q2′​=1.0nC=1.0×10−9C

  1. Apply Coulomb's law

Distance between spheres: r=0.5 mr = 0.5\,\text{m}r=0.5m

Electrostatic force: F=14πε0q1′q2′r2F = \frac{1}{4\pi\varepsilon_0}\frac{q_1'q_2'}{r^2}F=4πε0​1​r2q1′​q2′​​

Given: 14πε0=9×109\frac{1}{4\pi\varepsilon_0} = 9 \times 10^94πε0​1​=9×109

Substitute values: F=9×109×(1×10−9)(1×10−9)(0.5)2F = 9\times 10^9 \times \frac{(1\times 10^{-9})(1\times 10^{-9})}{(0.5)^2}F=9×109×(0.5)2(1×10−9)(1×10−9)​

F=9×109×10−180.25F = 9\times 10^9 \times \frac{10^{-18}}{0.25}F=9×109×0.2510−18​

F=9×109×4×10−18F = 9\times 10^9 \times 4\times 10^{-18}F=9×109×4×10−18

F=36×10−9 NF = 36\times 10^{-9}\,\text{N}F=36×10−9N

  1. Required integer

The force is written as: ‾×10−9 N\underline{\hspace{2cm}} \times 10^{-9}\,\text{N}​×10−9N

So the required integer is: 36\boxed{36}36​

  1. Comparison with stored answer

Stored correct answer = 36.

Our derived answer matches it.

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