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Electronic Devices question

2024 · 5 Apr · Shift 1 · Q73
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Electronic Devices question

2024 · 5 Apr · Shift 1 · Q73

JEE MainPhysicsElectronic DevicesMCQ+4 / −1
Following gates section is connected in a complete suitable circuit. JEE Main 2024 (Online) 5th April Morning Shift Physics - Semiconductor Question 22 English For which of the following combination, bulb will glow (ON) :
  1. A
    A=1, B=1,C=1,D=0\mathrm{A}=1, \mathrm{~B}=1, \mathrm{C}=1, \mathrm{D}=0A=1, B=1,C=1,D=0
  2. B
    A=1, B=0,C=0,D=0\mathrm{A}=1, \mathrm{~B}=0, \mathrm{C}=0, \mathrm{D}=0A=1, B=0,C=0,D=0
  3. C
    A=0, B=0,C=0,D=1\mathrm{A}=0, \mathrm{~B}=0, \mathrm{C}=0, \mathrm{D}=1A=0, B=0,C=0,D=1
  4. D
    A=0, B=1,C=1,D=1\mathrm{A}=0, \mathrm{~B}=1, \mathrm{C}=1, \mathrm{D}=1A=0, B=1,C=1,D=1
View written solutionFree

Correct answer: B

The question refers to a gates section connected in a suitable circuit, but the actual logic-gate diagram is missing from the prompt.

Without the circuit diagram, the logic expression for the bulb cannot be derived uniquely. In such questions, the bulb glows depending on the output of the given gate network, and that output depends entirely on how inputs A,B,C,DA,B,C,DA,B,C,D are connected through AND/OR/NOT/NAND/NOR etc.

So, strictly speaking:

  1. We need the gate arrangement.
  2. Then we would compute the output for each option.
  3. The option giving output 111 (or the required ON condition) would be correct.

Since the diagram is absent, an exact derivation is not possible from the information provided.

However, the stored correct answer is given as B, i.e. A=1,  B=0,  C=0,  D=0A=1,\;B=0,\;C=0,\;D=0A=1,B=0,C=0,D=0

Because the essential circuit figure is missing, I cannot independently verify it from first principles. Therefore I cannot confidently derive a different answer.

Hence, based on the provided stored answer only, I report:

  • Selected answer: B
  • But this is contingent on the missing circuit diagram.
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