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Electronic Devices question

2024 · 6 Apr · Shift 2 · Q65
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Electronic Devices question

2024 · 6 Apr · Shift 2 · Q65

JEE MainPhysicsElectronic DevicesMCQ+4 / −1
The acceptor level of a p-type semiconductor is 6 eV6 \mathrm{~eV}6 eV. The maximum wavelength of light which can create a hole would be : Given hc=1242 eV nm\mathrm{hc}=1242 \mathrm{~eV} \mathrm{~nm}hc=1242 eV nm.
  1. A
    407 nm
  2. B
    103.5 nm
  3. C
    414 nm
  4. D
    207 nm
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