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Electronic Devices question

2014 · Shift 0 · Q45
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Electronic Devices question

2014 · Shift 0 · Q45

JEE MainPhysicsElectronic DevicesMCQ+4 / −1
The current voltage relation of diode is given by I=(e100V/T−1)mA,{\rm I} = \left( {{e^{100V/T}} - 1} \right)mA,I=(e100V/T−1)mA, where the applied voltage VVV is in volts and the temperature TTT is in degree kelvin. If a student makes an error measuring ±0.01 V\pm 0.01\,V±0.01V while measuring the current of 5mA5mA5mA at 300K,300K,300K, what will be the error in the value of current on mAmAmA?
  1. A
    0.2mA0.2mA0.2mA
  2. B
    0.02mA0.02mA0.02mA
  3. C
    0.5mA0.5mA0.5mA
  4. D
    0.05mA0.05mA0.05mA
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