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Electronic Devices question

2010 · Shift 0 · Q51
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Electronic Devices question

2010 · Shift 0 · Q51

JEE MainPhysicsElectronic DevicesMCQ+4 / −1
The combination of gates shown below yields AIEEE 2010 Physics - Semiconductor Question 193 English
  1. A
    OR gate
  2. B
    NOT gate
  3. C
    XOR gate
  4. D
    NAND gate
View written solutionFree

Correct answer: A

The question asks for the output-equivalent gate of a combination of gates shown below, but the actual circuit diagram is not present in the provided prompt.

Without the gate diagram, it is not possible to rigorously derive the Boolean expression and identify the equivalent gate.

1. What is needed to solve this

To determine the resulting gate, we would normally:

  1. Read the circuit connections.
  2. Write the output of each intermediate gate.
  3. Simplify the Boolean expression.
  4. Match the final expression with one of the options:
    • OR: A+BA+BA+B
    • NOT: A‾\overline{A}A
    • XOR: A⊕B=A‾B+AB‾A\oplus B = \overline{A}B + A\overline{B}A⊕B=AB+AB
    • NAND: AB‾\overline{AB}AB

2. Limitation here

Since the circuit image is missing, the result cannot be independently verified from the information given.

3. Comparison with stored answer

The stored correct answer is A: OR gate. Because the diagram is absent, I cannot confirm this by derivation. Therefore, I should not claim agreement based on missing data.

If you upload or provide the gate combination diagram, I can solve it step-by-step and verify the exact answer.

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