- AIonic bonding
- BCovalent bonding
- CVander Waals bonding
- DMetallic bonding
View written solutionFree
Correct answer: B
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We are asked to identify the type of solid which:
- is not transparent to visible light, and
- has conductivity increasing with temperature.
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Let us analyze the given properties.
Property 1: Conductivity increases with temperature
This is a characteristic of semiconductors.
For semiconductors, as temperature increases, more charge carriers are generated, so conductivity increases.
In contrast, for metals, conductivity generally decreases with temperature due to increased lattice scattering.
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Now consider which bonding is associated with semiconductors.
Common semiconductors such as Si and Ge are solids with covalent bonding.
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Check the other options:
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A: Ionic bonding
Ionic solids are generally insulating in solid state and do not show typical semiconductor behavior. -
B: Covalent bonding
Covalent solids like silicon and germanium are semiconductors. They are not transparent to visible light in the usual sense and their conductivity increases with temperature. -
C: Vander Waals bonding
Molecular solids with van der Waals bonding are generally insulators. -
D: Metallic bonding
Metals are not transparent, but their conductivity decreases with temperature, so this does not match.
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Therefore, the solid described must be formed by covalent bonding.
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